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sum(r=0)^m .^(n+r)Cn is equal to...

`sum_(r=0)^m .^(n+r)C_n` is equal to

A

`""^(n+m+2)C_(n)`

B

`""^(n+m+1)C_(n+1)`

C

`""^(n+m+3)C_(n+1)`

D

`""^(n+m+1)C_(n-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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VMC MODULES ENGLISH-BINOMIAL THEOREM-LEVEL 2
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  3. sum(r=0)^m .^(n+r)Cn is equal to

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  4. Evaluate sum(i=0)^(n)sum(j=0)^(n) ""^(n)C(j) *""^(j)C(i), ile j .

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  6. The expression (""^(10)C(0))^(2)-(""^(10)C(1))^(2)+(""^(10)C(2))^(2)...

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  7. If C(0),C(1), C(2),...,C(n) denote the cefficients in the expansion...

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  8. If (1 + x)^(n) = C(0) + C(1) x + C(2) x^(2) +…+ C(n) x^(n) , find the...

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  9. If (1 + x)^(n) = C(0) + C(1) x + C(2) x^(2) +…+ C(n) x^(n) , find the...

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  10. If (1+x)^(n)=C(0)+C(1)x+C(2)x^(2)+….+C(n)x^(n), then the value of sums...

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  11. If (1+x)^(n)=C(0)+C(1)x+C(2)x^(2)+….+C(n)x^(n), then the value of sums...

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  14. If C(0),C(1),C(2),…,C(n) are the binomial coefficients in the expansio...

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  15. Find the sum of 1/(1!(n-1)!)+1/(3!(n-3)!)+1/(5!(n-5)!)+ ...,

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  18. Prove that ""^(n)C(3)+""^(n)C(7) + ""^(n)C(11) + ...= 1/2{2^(n-1) -...

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