Home
Class 12
MATHS
The equation of line passing through the...

The equation of line passing through the point `(3,2)` and perpendicular ot `y=x` is

A

`x-y=5`

B

`x+y=5`

C

`x+y=1`

D

`x-y=1`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    VMC MODULES ENGLISH|Exercise Level - 0 (Fill in the Blanks)|7 Videos
  • STRAIGHT LINES

    VMC MODULES ENGLISH|Exercise Level - 0 (True or False)|7 Videos
  • SEQUENCE AND SERIES

    VMC MODULES ENGLISH|Exercise JEE MAIN & Advance ( ARCHIVE)|46 Videos
  • THREE DIMENSIONAL GEOMETRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|34 Videos

Similar Questions

Explore conceptually related problems

The equation of the line passing through the point (1,2) and perpendicular to the line x+y+1=0 is

The equation of the line passing through the point (1,2) and perpendicular to the line x+y+1=0 is

Find the equation of the line passing through the point (5,2) and perpendicular to the line joining the points (2,3) and (3,-1).

Find the equation of a line passing through the point (-1,3,-2) and perpendicular to the lines: (x+2)/(-3)=(y-1)/(2)=(z+1)/5andx/1=y/2=z/3

Find the equation of line passing through the point (2,6) and perpendicular to (i) X-"axis" (ii) Y-"axis"

Find the equation of a line passing through the point (-1,0) and perpendicular to the line x+5y=4 .

The equation of the straight line passing through the point (3,2) and perpendicular to the line y=x is

The equation of the straight line passing through the point (3,2) and perpendicular to the line y=x is

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

Find the equation of the line passing through the point (2, 1, 3) and perpendicular to the lines (x-1)/1=(y-2)/2=(z-3)/3andx/(-3)=y/2=z/5