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The solution of the differential equatio...

The solution of the differential equation `(1+y^2)+(x-e^(tan^-1y))dy/dx=0` is (A) `x e^(2 tan^-1y)=e^(tan^-1y)+k` (B) `(x-2)=k e^(-tan^-1y)` (C) `2 x e^(tan^-1y)=e^(2 tan^-1y)+k` (D) `x e^(tan^-1y)=tan^-1y+k`

A

`(x-2)=Ke ^(tan ^(-1))y`

B

`2 Xe ^( tan ^(-1)) y= tan ^(-1)y+K`

C

`Xe tan ^(-1) Y= tan ^(-1) y+K`

D

`Xe ^2 tan ^(-1)y= tan ^(-1) y+K`

Text Solution

Verified by Experts

The correct Answer is:
B
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VMC MODULES ENGLISH-DIFFERENTIAL EQUATIONS-JEE ADVANCE (ARCHIVE )
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