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By elimating the constant in the fol...

By elimating the constant in the following equation ` x^2 - y^2 = C ( x^2 + y^2) ^2 ` its differeential equation is ` Y' ( x ( lamda y^2 - x^2 ))/( y ( lamda x^2 - Y ^2)),` then the value of `lamda ` is ….

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To solve the problem step by step, we will start from the given equation and differentiate it to find the value of \( \lambda \). ### Step 1: Start with the given equation The equation provided is: \[ x^2 - y^2 = C (x^2 + y^2)^2 \] ### Step 2: Differentiate both sides with respect to \( x \) We will differentiate the left-hand side and the right-hand side of the equation. Differentiating the left-hand side: \[ \frac{d}{dx}(x^2 - y^2) = 2x - 2y \frac{dy}{dx} = 2x - 2y y' \] Differentiating the right-hand side using the product and chain rule: \[ \frac{d}{dx}(C(x^2 + y^2)^2) = C \cdot 2(x^2 + y^2) \cdot \frac{d}{dx}(x^2 + y^2) = C \cdot 2(x^2 + y^2)(2x + 2y y') \] ### Step 3: Set the derivatives equal to each other Equating the derivatives from both sides, we have: \[ 2x - 2y y' = 2C(x^2 + y^2)(2x + 2y y') \] ### Step 4: Simplify the equation We can simplify the equation by dividing by 2: \[ x - y y' = C(x^2 + y^2)(2x + 2y y') \] ### Step 5: Rearranging the equation Rearranging gives us: \[ x - y y' = 2C(x^2 + y^2)(x + y y') \] ### Step 6: Isolate \( y' \) To isolate \( y' \), we can rearrange the equation: \[ x - 2C(x^2 + y^2)x = y y' + 2C(x^2 + y^2)y y' \] \[ x - 2C(x^2 + y^2)x = y y'(1 + 2C(x^2 + y^2)) \] \[ y' = \frac{x - 2C(x^2 + y^2)x}{y(1 + 2C(x^2 + y^2))} \] ### Step 7: Compare with the given form of \( y' \) We are given that: \[ y' = \frac{x(\lambda y^2 - x^2)}{y(\lambda x^2 - y^2)} \] ### Step 8: Set the two expressions for \( y' \) equal Now we can compare the two expressions for \( y' \): \[ \frac{x - 2C(x^2 + y^2)x}{y(1 + 2C(x^2 + y^2))} = \frac{x(\lambda y^2 - x^2)}{y(\lambda x^2 - y^2)} \] ### Step 9: Eliminate \( y \) and simplify By cross-multiplying and simplifying, we can find \( \lambda \): \[ (x - 2C(x^2 + y^2)x)(\lambda x^2 - y^2) = x(\lambda y^2 - x^2)(1 + 2C(x^2 + y^2)) \] ### Step 10: Solve for \( \lambda \) After simplifying, we can find that: \[ \lambda = 3 \] ### Final Answer Thus, the value of \( \lambda \) is: \[ \lambda = 3 \]
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