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Tangent is drawn at any point P of a cur...

Tangent is drawn at any point P of a curve which passes through (1, 1) cutting x-axis and y-axis at A and B respectively. If AP:BP = 3:1, then ,

A

differential equation of the curve is ` 3x ( dy)/(dx) + y =0`

B

differential equation of the curve is ` 3x (dy )/(dx) - y=0`

C

curve is passing through ` (1/8 ,2)`

D

normal at ` (1,1 ) ` is ` x + 3y = 4`

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The correct Answer is:
A, C
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