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Arrange the F(2), F(2)^(+) and F(2)^(-) ...

Arrange the `F_(2), F_(2)^(+)` and `F_(2)^(-)` in increasing order of bond energies.

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To arrange \( F_2 \), \( F_2^+ \), and \( F_2^- \) in increasing order of bond energies, we need to analyze the bond order of each species, as bond energy is directly related to bond order. Here’s a step-by-step solution: ### Step 1: Determine the number of electrons in each species - **For \( F_2 \)**: Each fluorine atom has 7 electrons, so \( F_2 \) has a total of \( 7 + 7 = 14 \) electrons. - **For \( F_2^+ \)**: This species has one less electron than \( F_2 \), so it has \( 14 - 1 = 13 \) electrons. - **For \( F_2^- \)**: This species has one more electron than \( F_2 \), so it has \( 14 + 1 = 15 \) electrons. ### Step 2: Calculate the bond order for each species ...
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