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The bond dissociation energy of N(2)^(+...

The bond dissociation energy of `N_(2)^(+)` is less than that of `N_(2)` . Show why this is the case.

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E.C. of `N_(2): (sigma_(1s))^(2) (sigma_(1s)^(**))^(2) (sigma_(2s))^(2) (sigma_(2s)^(**))^(2) (pi 2px)^(2)(pi 2py)^(2)(sigma 2p_(z))^(1)`
E.C. of `N_(2)^(+) : (sigma_(1s))^(2) (sigma_(1s)^(**))^(2) (sigma_(2s))^(2) (sigma_(2s)^(**))^(2) (pi 2p_(x))^(2)(pi 2p_(y))^(2)(sigma 2p_(z))^(1)`
Bond order of `N_(2)=(10-4)/(2)=3` , Bond order of `N_(2)^(+) =(9-4)/(2)=2.5`
Bond energy `prop` bond order , Bond energy of `N_(2)^(+) lt N_(2) therefore` Bond dissociation energy of `N_(2)^(+)` is less than `N_(2)`
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