There are …………. `pi` bonds in a nitrogen molecule

Explanation

To determine the number of pi bonds in a nitrogen molecule (N₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Structure of Nitrogen**:
- Nitrogen (N) has an atomic number of 7, which means it has 7 electrons. The electron configuration is 1s² 2s² 2p³. The valence shell (2nd shell) has 5 electrons (2 from 2s and 3 from 2p).

2. **Determine the Valence Electrons**:
- In the case of nitrogen, each nitrogen atom has 5 valence electrons (2 from the 2s orbital and 3 from the 2p orbitals).

3. **Bond Formation in N₂**:
- When two nitrogen atoms come together to form a nitrogen molecule (N₂), they share electrons to achieve a stable electron configuration. Each nitrogen atom will share 3 of its valence electrons with the other nitrogen atom.

4. **Identify the Type of Bonds Formed**:
- In N₂, the bonding involves one sigma bond and two pi bonds.
- The sigma bond is formed by the head-on overlap of orbitals (specifically, the sp hybrid orbitals), while the pi bonds are formed by the sidewise overlap of the p orbitals.

5. **Count the Pi Bonds**:
- Since there are two pi bonds formed in the nitrogen molecule (N₂), the answer to the question is that there are **2 pi bonds** in a nitrogen molecule.

### Final Answer:
There are **2 pi bonds** in a nitrogen molecule (N₂).

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