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On hydridisation of one s and one p-orbi...

On hydridisation of one s and one p-orbitals , we get

A

two mutually perpendicular orbitals

B

two orbitals at `180^(@)`

C

four orbitals directed tetrahedrally

D

three orbitals in a plane

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The correct Answer is:
B
Hybridisation of one ‘s’ and one ‘p’ orbitals gives two sp hybrid orbitals oriented linearly at `180^(@)`.
`s+p to 2sp` hybrid orbitals
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According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

VMC MODULES ENGLISH-CHEMICAL BONDING-I & II-JEE Advanced (Archive)
  1. Carbon tetrachloride has no net dipole momnet because of .

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  2. Linear overlap of two atomic p-orbitals leads to a sigma bond .

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  3. On hydridisation of one s and one p-orbitals , we get

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  4. SnCI(2) is a non-linear molecule .

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  5. The hybridisaton of sulphur in sulphur dioxide is .

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  6. CO(2) is isostructural with

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  7. The bond between two indentical non-metal atoms has a pair of electron...

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  8. sp^(3) hybrid orbitals have equal s and p characters .

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  9. In benzene, carbon uses all the three p-orbitals for hybridisation .

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  10. The Cl-C-Cl angle is 1,1,2,2-tetrachloroethene and tetrachloromethane ...

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  11. The molecule that has linear structure is

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  12. The species in which the central atom uses sp^(2) hybrid orbitals in i...

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  13. The molecule which has pyramidal shape is

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  14. Which of the following is paramagnetic ?

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  15. The molecule which has zero dipole momnet is .

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  16. The valence atomic orbital on C in silver acetylide is ……………hybridised...

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  17. Between Na^(+) and Ag^(+) , which is stronger Lewis acid and why?

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  18. The shape of [CH(3)]^(o+) is .

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  19. The presnce of polar bonds in a polyatomic molecule suggests that the ...

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  20. What effect should the following resonance of vinyl chloride have on i...

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