According to `MO` theory .

Options

A. `O_(2)^(+)` is paramagnetic and bond order greater than `O_(2)`
B. `O_(2)^(+)` is paramagnetic and bond order less than `O_(2)`
C. `O_(2)^(+)` is diamagnetic and bond order is less than `O_(2)`
D. `O_(2)^(+)` is diamagnetic and bond order is more than `O_(2)`

Answer

A

Explanation

`O_(2)^(+)(15e^(-)):sigma1s^(2)overset(***)sigma1s^(2)sigma2s^(2)overset(***)sigma2s^(2)sigma2p_(x)^(2)|(pi2p_(y)^(2)),(pi2p_(z)^(2))||(overset(***)pi2p_(y)^(1)),(overset(***)pi2p_(z)^(0))|overset(***)sigma2p_(x)^(0)` Bond order `=(10-5)/(2)=2.5`,paramagnetic.
`O_(2)(16e^(-)):sigma1s^(2)overset(***)sigma1s^(2)sigma2s^(2)overset(***)sigma2s^(2)sigma2p_(x)^(2)|(pi2p_(y)^(2)),(pi2p_(z)^(2))||(overset(***)pi2p_(y)^(1)),(overset(***)pi2p_(z)^(1))|overset(***)sigma2p_(x)`
Bond order `=(10-6)/(2)=2`. Hence, (A) is the correct answer.