An open vessel at `27^@C` is heated until three fifth of the air in it has been expelled। Assuming volume of vessel constant find the temperature to which the vessel has been heated

Explanation

One should clearly note the fact that on heating a gas in a vessel there are the number of moles of gas which go out, the volume of vessel remains constant.
Let initial moles of gas at 300 K be ‘n’. On heating 3/5 moles of air are escaped out at temperature T.
`:.` Moles of air left at temperature `T =(n-(3)/(5) n) = (2n)/(5)`
Under similar conditions of P and V
`n_(1)T_(1) = n_(2)T_(2), n xx 300 = (2n)/(5) xx T, T = 750 K`