The VD of gas is 11.2. The volume occupied by 11.2g of this gas at NTP is:

Options

A. 22.4 L
B. 11.2 L
C. 1 L
D. 2.2 L

Explanation

To solve the problem of finding the volume occupied by 11.2 g of a gas with a vapor density of 11.2 g at NTP (Normal Temperature and Pressure), we can follow these steps:

### Step-by-Step Solution:

1. **Understand Vapor Density**:
- The vapor density (VD) of a gas is defined as the mass of a certain volume of the gas compared to the mass of an equal volume of hydrogen at the same temperature and pressure. It is given as 11.2 g.

2. **Calculate Molar Mass**:
- The molar mass (M) of a gas can be calculated using the formula:
\[ M = 2 \times \text{Vapor Density} \]
- Substituting the given vapor density:
\[ M = 2 \times 11.2 \, \text{g} = 22.4 \, \text{g/mol} \]

3. **Volume at NTP**:
- At NTP, 1 mole of any gas occupies a volume of 22.4 liters. Therefore, the volume occupied by 22.4 g of the gas (which is 1 mole) is:
\[ \text{Volume} = 22.4 \, \text{L} \]

4. **Calculate Volume for 11.2 g**:
- To find the volume occupied by 11.2 g of the gas, we can set up a proportion based on the volume occupied by 22.4 g:
\[ \text{Volume occupied by 11.2 g} = \frac{22.4 \, \text{L}}{22.4 \, \text{g}} \times 11.2 \, \text{g} \]
- Simplifying this gives:
\[ \text{Volume occupied by 11.2 g} = 11.2 \, \text{L} \]

5. **Final Answer**:
- Therefore, the volume occupied by 11.2 g of the gas at NTP is:
\[ \text{Volume} = 11.2 \, \text{L} \]

### Conclusion:
The volume occupied by 11.2 g of this gas at NTP is **11.2 liters**.

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