A gas at a pressure of 5 atm is heated from `0^(@)` to `546^(@)` C and simultaneously compressed to `(1)/(3)` rd of it original volume . Hence final pressure is

Options

A. 15.0 atm
B. 30.0 atm
C. 45.0 atm
D. `5//9` atm

Answer

C

Explanation

Use `(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2)) rArr P_(2) = (P_(1)V_(1))/(T_(1)) xx (T_(2))/(V_(2)) = (5 xx cancel(V_(1)))/(cancel(2731)) xx (cancel(819)3)/((cancel(V_(1))//3)) = 45 " atm "`