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According to Graham's law, at a given te...

According to Graham's law, at a given temperature the ratio of diffusion `r_A/r_B` of gases A and B is given by
(where P and M are pressures and molecular weights of gases A and B respectively)

A

`(p_(A)//p_(B)) (M_(A)//M_(B))^(1//2)`

B

`(M_(A)//M_(B)) (p_(A)//p_(B))^(1//2)`

C

`(p_(A)//p_(B)) (M_(B)//M_(A))^(1//2)`

D

`(M_(A)//M_(B)) (p_(B)//P_(A))^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`(r_(A))/(r_(B)) = (P_(A))/(P_(B)) sqrt((M_(B))/(M_(A)))`
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