A ballon filled with ethyne is pricked with a sharp point and quickly dropped in a tank of `H_(2)` gas under indentical conditions. After a while the balloon will

Options

A. Shrunk
B. Enlarged
C. Completely collapsed
D. Remained unchanged in size

Explanation

To solve the question, let's analyze the situation step by step:

### Step 1: Understand the Scenario
A balloon filled with ethyne (C2H2) is pricked, creating a hole, and then it is dropped into a tank of hydrogen gas (H2).

**Hint:** Consider the properties of gases and how they behave in different conditions.

### Step 2: Identify the Gases Involved
- **Inside the Balloon:** Ethyne (C2H2)
- **Outside the Balloon:** Hydrogen (H2)

**Hint:** Recall the molecular weights and properties of the gases involved.

### Step 3: Compare the Rates of Diffusion
According to Graham's law of effusion, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. Hydrogen (H2) has a lower molar mass compared to ethyne (C2H2), which means hydrogen diffuses faster than ethyne.

**Hint:** Use Graham's law to understand which gas will diffuse more quickly.

### Step 4: Analyze the Effect of Diffusion
Since hydrogen diffuses faster, it will move into the balloon through the hole created when the balloon was pricked. As hydrogen enters the balloon, it will increase the volume of the gas inside the balloon.

**Hint:** Think about what happens to the volume of the balloon when a lighter gas enters it.

### Step 5: Conclusion
As a result of hydrogen gas diffusing into the balloon, the balloon will enlarge. Therefore, the correct answer to the question is that the balloon will **enlarge**.

**Final Answer:** The balloon will enlarge.