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At identical temperature and pressure, t...

At identical temperature and pressure, the rate of diffusion of hydrogen gas is `3sqrt(3)` times that of a hydrocarbon having molecular formula `C_(n)H_(2n-2)`. What is the value of n ?

A

n = 2

B

n = 4

C

n = 3

D

n = 1

Text Solution

Verified by Experts

The correct Answer is:
B
`(r_(x))/(r_(H_(2))) = (1)/(3sqrt3) sqrt((m_(H_(2)))/(M_(X))) rArr M_(X) = 54 gm = 12n + (2n-2) rArr 14n = 56 rArr n=4`
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