The graph of P vs V is given at different temperature

The correct relationship is

Options

A. `(a)/(b) lt 0.4 k cal mol^(-1)`
B. `0.4 cal mol^(-1) lt (a)/(b) lt 2 k cal mol^(-1)`
C. `(a)/(b) gt 0.4 k cal mol^(-1)`
D. `(a)/(b) = 1 k cal mol^(-1)`

Answer

D

Explanation

Check that 500 K is Boyle’s Temperature.`rArr 500 = (a)/(2 xx b) rArr (a)/(b) = 1 k cal mol^(-1)`