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At Boyle's temperature the value of comp...

At Boyle's temperature the value of compressibility factro `Z = (PV_(m(//RT = V_(real)//V_(ideal))` has a value of 1 over a wide range of pressure. This is due to the fact that in the van der Waal's equation

A

The constant ‘a’ is negligible and not ‘b’

B

The constant ‘b’ is negligible and not ‘a’

C

Both the constant ‘a’ and ‘b’ are negligible

D

The effect produced due to the molecular attraction compensates the effect produced due to the molecular volume

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To solve the question regarding Boyle's temperature and the compressibility factor \( Z \) in the context of the van der Waals equation, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Compressibility Factor**: The compressibility factor \( Z \) is defined as: \[ Z = \frac{PV_m}{RT} \] where \( P \) is the pressure, \( V_m \) is the molar volume, \( R \) is the universal gas constant, and \( T \) is the temperature. 2. **Definition of Boyle's Temperature**: Boyle's temperature is defined as the temperature at which a real gas behaves like an ideal gas over a range of pressures. At this temperature, the compressibility factor \( Z \) approaches 1. 3. **Van der Waals Equation**: The van der Waals equation for real gases is given by: \[ \left( P + \frac{a n^2}{V^2} \right)(V - nb) = nRT \] where \( a \) and \( b \) are the van der Waals constants that account for intermolecular forces and the volume occupied by gas molecules, respectively. 4. **Behavior at Boyle's Temperature**: At Boyle's temperature, the effects of the van der Waals constants \( a \) and \( b \) become negligible. This means that the intermolecular forces and the volume occupied by the gas molecules do not significantly affect the behavior of the gas. 5. **Reduction to Ideal Gas Law**: When \( a \) and \( b \) are negligible, the van der Waals equation simplifies to: \[ PV = nRT \] This is the ideal gas equation, which implies that: \[ Z = \frac{PV}{RT} = 1 \] 6. **Conclusion**: Therefore, at Boyle's temperature, the compressibility factor \( Z \) equals 1 because the van der Waals constants \( a \) and \( b \) are negligible, allowing the gas to behave ideally. ### Final Answer: At Boyle's temperature, the value of compressibility factor \( Z = 1 \) over a wide range of pressure due to the fact that in the van der Waals equation, the constants \( a \) and \( b \) become negligible, leading the equation to approximate the ideal gas law.

To solve the question regarding Boyle's temperature and the compressibility factor \( Z \) in the context of the van der Waals equation, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Compressibility Factor**: The compressibility factor \( Z \) is defined as: \[ Z = \frac{PV_m}{RT} ...
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Compressibility factor, Z of a gas is given as Z=(pV)/(nRT) (i) What is the value of Z for an ideal gas ? (ii) For real gas what will be the effect on value of Z above boyle's temperature ?

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The internal pressure loss of 1 mol of van der Waals gas over an ideal gas is equal to

Boyle's temperature or Boyle point is the temperature at which a real gas starts behaving like an ideal gas over a particular range of pressure. A graph is plotted between compressibility factor Z and pressure P. What is the deviation of real gas from ideal behaviour in terms of compressibility factor , Z ?

Boyle's temperature or Boyle point is the temperature at which a real gas starts behaving like an ideal gas over a particular range of pressure. A graph is plotted between compressibility factor Z and pressure P. What is the variation of Z with pressure ?

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For a real gas , the compressibility factor Z has different values at different temperatures and pressures . Which of the following is not correct under the given conditions ?

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