Points I, II and III in the following plot respectively correspond to (`V_(mp)`: most probable velocity)

Options

A. `V_(m p) " of " N_(2) (300 K), V_(m p) " of " H_(2) (300 K) , V_(m p) " of " O_(2) (400 K)`
B. `V_(m p) " of " N_(2) (300 K), V_(m p) " of " O_(2) (400 K), V_(m p) " of " H_(2) (300 K)`
C. `V_(m p) " of " H_(2) (300 K), V_(m p) " of " N_(2) (300 K), V_(m p) " of " O_(2) (400K)`
D. `V_(m p) " of " O_(2) (400 K), V_(m p) " of " N_(2) (300 K), V_( m p) " of " H_(2) (300 K)`

Answer

B

Explanation

`V_(m p) = sqrt((2RT)/(M))`, where R `rArr` universal gas constant `rArr` Temperature `rArr` Molar mass
Greater the `(T)/(M)` ratio, greater will be the speed and higher the speed, the graph will shift towards right