3.7 g of a gas at 25°C occupies the same volume as 0.184 g of hydrogen at 17°C and at the same pressure. What is the molecular mass of the gas ?

Answer

(14.32 g)

Explanation

For same p and V,`n prop (1)/(T) rArr (n ("gas"))/(n(H_(2))) = (T(H_(2)))/(T("gas")), n(H_(2)) = (0.184)/(2) = 0.092`
`rArr n("gas") = (290)/(298) xx 0.092 = 0.0895 , :'` 0.0985 mole of gas weigh 3.7 g
`:.` 1 mole of gas will weigh `(3.7)/(0.0895) = 41.32g`