According to Graham's law, at a given temperature the ratio of diffusion `r_A/r_B` of gases A and B is given by
(where P and M are pressures and molecular weights of gases A and B respectively)

Options

A. `((p_(A))/(p_(B))) ((M_(A))/(M_(B)))^((1)/(2))`
B. `((M_(A))/(M_(B))) ((p_(A))/(p_(B)))^((1)/(2))`
C. `((p_(A))/(p_(B))) ((M_(B))/(M_(A)))^((1)/(2))`
D. `((M_(A))/(M_(B))) ((p_(B))/(p_(A)))^((1)/(2))`

Answer

C

Explanation

`(p_(A))/(p_(B)) = (n_(A))/(n_(B)) sqrt((M_(B))/(M_(A)))` (at constant T and V)