The density of the vapour of a substance at 1 atm pressure and 500 K is 0.36 kg `m^(-3)`. The vapour effuses through a small hole at a rate of 1.33 times faster than oxygen under the same condition.
If the vapour behaves ideally at 1000 K, determine the average translational kinetic energy of a molecule.

Explanation

`bar(E ) = (3)/(2) k_(B) T = (3)/(2) xx 1.38 xx 10^(-23) xx 1000 J = 2.07 xx 10^(-20) J`