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Which of the following is/are correct re...

Which of the following is/are correct regarding root mean square speed `(U_(rms))` & average translation K.E. `(E_(av))` of molecules in a gas at equilibrium

A

`U_(rms)` is inversely proportional to square root of its molecular mass

B

`U_(avg)` at a given temperature does not depend on its molecular mass

C

`U_(avg)` is doubled when its temperature is increased four times

D

`U_(rms)` is doubled when its temperature is increased four times

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The correct Answer is:
To solve the question regarding the root mean square speed `(U_(rms))` and average translational kinetic energy `(E_(av))` of molecules in a gas at equilibrium, we will analyze each statement provided in the question based on the relevant formulas. ### Step-by-Step Solution: 1. **Understanding the Formulas**: - The root mean square speed `(U_(rms))` is given by the formula: \[ U_{rms} = \sqrt{\frac{3RT}{m}} \] where \( R \) is the gas constant, \( T \) is the temperature, and \( m \) is the molecular mass of the gas. - The average translational kinetic energy `(E_(av))` is given by the formula: \[ E_{av} = \frac{3}{2} RT \] 2. **Analyzing Statement 1**: - **Statement**: "Root mean square speed is inversely proportional to the square root of its molecular mass." - **Analysis**: From the formula for \( U_{rms} \), we see that \( U_{rms} \) is inversely proportional to the square root of \( m \) (molecular mass). Thus, this statement is **correct**. 3. **Analyzing Statement 2**: - **Statement**: "Average translational kinetic energy at a given temperature does not depend on its molecular mass." - **Analysis**: In the formula for \( E_{av} \), there is no \( m \) (molecular mass) present. Therefore, the average translational kinetic energy is independent of molecular mass at a given temperature. This statement is also **correct**. 4. **Analyzing Statement 3**: - **Statement**: "Average translational kinetic energy is doubled when its temperature is increased four times." - **Analysis**: Since \( E_{av} \) is directly proportional to \( T \), if \( T \) is increased four times, \( E_{av} \) will also increase four times, not double. Thus, this statement is **incorrect**. 5. **Analyzing Statement 4**: - **Statement**: "Root mean square speed is doubled when its temperature is increased four times." - **Analysis**: Since \( U_{rms} \) is proportional to \( \sqrt{T} \), if \( T \) is increased four times, \( \sqrt{T} \) will increase by a factor of 2 (since \( \sqrt{4} = 2 \)). Therefore, \( U_{rms} \) will indeed be doubled. This statement is **correct**. ### Conclusion: The correct statements regarding root mean square speed and average translational kinetic energy are: - Statement 1: Correct - Statement 2: Correct - Statement 3: Incorrect - Statement 4: Correct Thus, the correct options are 1, 2, and 4.

To solve the question regarding the root mean square speed `(U_(rms))` and average translational kinetic energy `(E_(av))` of molecules in a gas at equilibrium, we will analyze each statement provided in the question based on the relevant formulas. ### Step-by-Step Solution: 1. **Understanding the Formulas**: - The root mean square speed `(U_(rms))` is given by the formula: \[ U_{rms} = \sqrt{\frac{3RT}{m}} ...
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