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A natural gas may be assumed to be a mix...

A natural gas may be assumed to be a mixture of `CH_4 and C_2H_6` only. On complete combustion of 10 L of the gas at STP, the heat evolved was 474.6 kJ. Assuming `DeltaHc(CH_4) = – 894 kJ//mol and " "DeltaHC(C_2H_6) = - 1560 kJ//"mole"`. Calculate the % by volume of each gas in the mixture

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To solve the problem, we need to determine the percentage by volume of each gas (CH₄ and C₂H₆) in a natural gas mixture based on the heat evolved during combustion. Here’s the step-by-step solution: ### Step 1: Define Variables Let: - \( x \) = volume of CH₄ (in liters) - \( 10 - x \) = volume of C₂H₆ (in liters) ### Step 2: Calculate Moles of Each Gas ...
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