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If equilibrium constant for the reaction...

If equilibrium constant for the reaction
`A_(2)+B_(2) hArr 2AB` is k, then for the backward reaction `AB hArr 1//2 A_(2)+1//2B_(2)` the equilibrium constant k' is `1//K`.

Text Solution

Verified by Experts

`R xx n` is reversed and multiplied by 1/2 . So `K_(new)^(eq) = sqrt(1/K)`
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