Addition of HBr to propene yields 2-bromopropane, while in the presence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give mechanism.

Assertion: Addition of HBr to propene yields 2-bromopropane but in presence of a peroxide it yields 1-bromopropane. Reason: When reaction is carried out in the presence of a peroxide it follows free radical mechanism, 2^(@) free radical is more stable than 1^(@) free radical.

When HCl gas is passed through propene in the presence of benzoyl peroxide, it gives :

When HBr adds to 1-butene in the presence of benzoyl peroxide, the product obtained is

Why is in the presence of diethyl peroxide, the addition of HBr to propene is against Markownikoff's rule?

Reaction of HBr with propene in the presence of peroxide gives :-

The reaction of HBr with 1-propene in the presence of peroxides will produce primarily

Reaction of HBr with propene, in absence of organic peroxides, gives 1-bromopropane as the major product.

sp^2, sp^3 , polar, non-polar, gem, vicinal, 2, 3, Grove's, Darzen, Markownikov's rule, Kharasch, increase, decrease Addition of HBr to propene, in presence of organic peroxides, gives 1-bromopropane as the major product. It is called ....... effect.

The reaction intermediates involved in the addition of HBr to propene in the presence of an organic peroxide are (a) free radicals (b)carbocations (c)carbanions (d)carbenes

In the presence of peroxide addition of HBr to propene takes place according to anti Markownikoff's rule but peroxide effect is not seen in the case of HCl and HI. Explain.