p-Hydroxybenzophenone upon reaction with bromine in carbon tetrachloride gives:

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Answer

To solve the problem of what p-hydroxybenzophenone gives upon reaction with bromine in carbon tetrachloride, we can follow these steps:

### Step 1: Understand the Structure of p-Hydroxybenzophenone
- p-Hydroxybenzophenone consists of two benzene rings connected by a carbonyl (C=O) group. One of the benzene rings has a hydroxyl (-OH) group at the para position relative to the carbonyl group.

### Step 2: Identify the Electrophilic Substitution Reaction
- The presence of the hydroxyl group (-OH) on the benzene ring activates the ring towards electrophilic substitution due to its +M (mesomeric) effect. This means that the -OH group can donate electron density to the benzene ring, making it more reactive towards electrophiles like bromine.

### Step 3: Determine the Position of Bromine Substitution
- In electrophilic aromatic substitution reactions, the bromine will preferentially substitute at the ortho or para positions relative to the -OH group. Since the -OH group is at the para position, the bromine can attack either the ortho or para positions. However, steric hindrance will favor the ortho position for substitution.

### Step 4: Draw the Product Structure
- After the bromine reacts with the ortho position of the benzene ring, the product will have a bromine atom attached to the ortho position of the benzene ring that is already substituted with the -OH group. The carbonyl group remains unchanged.

### Step 5: Write the Final Product
- The final product can be represented as follows:
- The structure will still contain the two benzene rings, the carbonyl group (C=O), and now a bromine atom attached to the ortho position of the benzene ring with the -OH group.

### Final Answer
The product of the reaction of p-hydroxybenzophenone with bromine in carbon tetrachloride is 2-bromo-p-hydroxybenzophenone.

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