One mole of a hydrocarbon `'A'` reacts with `1 mil` of brominne giving a dibromo compound, `C_(5)H_(10)Br_(2)`. Compound `'A'` on treatment with cold dilute alkaline potassium permanganate solution forms a compound, `C_(5)H_(12)O_(2)`. On ozonolysis, `'A'` gives equimolar quantities of propanone and ethanal. Deduce the structural formula of `'A'`

The compound which gives H_2O_2 on treatment with dilute acid is

An organic compound E (C_5 H_8) on hydrogenation gives compound F (C_5 H_(12) ) . Compound E on ozonolysis gives formaldehyde and 2-ketopropanal. Deduce the structure of compound E.

An organic compound with molecular formula C_6 H_(12) upon ozonolysis gives only acetone as the product. The compound is :

Optically active isomer (A) of (C_(5)H_(9)Cl) on treatment with one mole of H_(2) gives an optically inactive compound (B) compound (A) will be :

A hydrocarbon (X) of the formula C_6H_12 does not react with bromine water but reacts with bromine in presence of light, forming compound (Y).Compound (Y) on treatment with Alc. KOH gives compound (Z) which on ozonolysis gives (T) reduces Tollens reagent which gives compound (W) after acidification . (W) gives iodoform test and after acidification produce compound (U) which when heated with P_2O_5 forms a cyclic anhydride (V). Compound V is

A hydrocarbon (X) of the formula C_6H_12 does not react with bromine water but reacts with bromine in presence of light, forming compound (Y).Compound (Y) on treatment with Alc. KOH gives compound (Z) which on ozonolysis gives (T) reduces Tollens reagent which gives compound (W) after acidification . (W) gives iodoform test and after acidification produce compound (U) which when heated with P_2O_5 forms a cyclic anhydride (V). Compound W is

A hydrocarbon (X) of the formula C_6H_12 does not react with bromine water but reacts with bromine in presence of light, forming compound (Y).Compound (Y) on treatment with Alc. KOH gives compound (Z) which on ozonolysis gives (T) reduces Tollens reagent which gives compound (W) after acidification . (W) gives iodoform test and after acidification produce compound (U) which when heated with P_2O_5 forms a cyclic anhydride (V). Compound 'x' is

A hydrocarbon C_(5)H_(10) does not react with chlorine in dark but gives a single monochloro compound C_(5)H_(9)Cl in bright sunlight. Identify the hydrocarbon.