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In a gas discharge tube, if 3 times 10^1...

In a gas discharge tube, if `3 times 10^18` electrons are flowing per sec from left to right and `2 times 10^18` protons are flowing per second from right to left of a given cross-section, the magnitude and direction of current through the cross-section :

A

0.48 A, left to right

B

0.48 A, right to left

C

0.80 A, left to right

D

0.80 A, right to left

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the total current flowing through the cross-section of the gas discharge tube due to the movement of electrons and protons. ### Step-by-Step Solution: 1. **Identify the flow of charge carriers**: - Electrons are flowing from left to right at a rate of \(3 \times 10^{18}\) electrons per second. - Protons are flowing from right to left at a rate of \(2 \times 10^{18}\) protons per second. ...
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