The thermal coefficient of resistivity for a material is `10^-3``/^@C`. A potential difference 100 V is applied across a conductor made out of this material at `20^@C`. Initially, the rate of total heat dissipation in the conductor is `H_0`. After some time, the conductor achieves an equilibrium temperature `100^@C` . The rate of total heat dissipation at this temperature is H .The ratio `H_0/H` is _____

Explanation

To solve the problem, we need to find the ratio \( \frac{H_0}{H} \), where \( H_0 \) is the initial rate of heat dissipation and \( H \) is the rate of heat dissipation at the equilibrium temperature.

### Step-by-Step Solution:

1. **Understand the relationship between heat dissipation and resistance:**
The rate of heat dissipation \( H \) in a conductor can be expressed using the formula:
\[
H = \frac{V^2}{R}
...