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In the circuit shown, current through th...

In the circuit shown, current through the resistance`2Omega` is`i_1` and current through the resistance`30Omega` is `i_2`. The ratio `i_1/i_2` is equal to

Text Solution

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Potentials are indicated in figure
Current in `2Omega=(10-(-5))/2=15/2=7.5A` leftwards
Current, in `30 Omega=(10-(-15))/30=25/30=5/6A` downwards
`i_1/i_2=9`
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