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An unknown resistance R(1) is connected ...

An unknown resistance `R_(1)` is connected is series with a resistance of `10 Omega`. This combination is connected to one gap of a meter bridge, while other gap is connected to another resistance `R_(2)`. The balance point is at `50 cm` Now , when the `10 Omega` resistance is removed, the balanced point shifts to `40 cm` Then the value of `R_(1)` is.

A

20

B

10

C

60

D

80

Text Solution

Verified by Experts

`(R_1+10)R_2=50/50`……(i) [Case 1]
`R_1/R_2=40/60`…….(ii) [Case 2]
An solving (i) and (ii) we get `R_1=20 Omega and R_2=30 Omega`
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