Home
Class 12
PHYSICS
In the circuit shown below, the internal...


In the circuit shown below, the internal resistance of the cell is negligible. The distance of the slider from the left-hand end of the slide wire is l. The graph shows the variation with l of the current I in the cell.
The balance point is at length l that is equal to:

A

0cm

B

20cm

C

30cm

D

40cm

Text Solution

Verified by Experts

From given graph at l=20cm,I=0mA
Promotional Banner

Topper's Solved these Questions

  • DC CIRCUIT

    VMC MODULES ENGLISH|Exercise LEVEL-2 DAILY TUTORIAL SHEET-4|10 Videos
  • DC CIRCUIT

    VMC MODULES ENGLISH|Exercise LEVEL-2 DAILY TUTORIAL SHEET-5|10 Videos
  • DC CIRCUIT

    VMC MODULES ENGLISH|Exercise LEVEL-2 DAILY TUTORIAL SHEET-2|10 Videos
  • CURRENT ELECTRICITY

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|10 Videos
  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) Level - II (SINGLE OPTION CORRECT TYPE )|31 Videos

Similar Questions

Explore conceptually related problems

In the circuit shown below, the internal resistance of the cell is negligible. The distance of the slider from the left-hand end of the slide wire is l. The graph shows the variation with l of the current I in the cell. E.M.F. of the cell is:

In the circuit shown below, the internal resistance of the cell is negligible. The distance of the slider from the left-hand end of the slide wire is l. The graph shows the variation with l of the current I in the cell. Value of the resistance R is:

In the circuit shown , the internal resistance of the cell is negligible . The steady stale current in the 2 Omega resistor is

In the circuit shows in Fig. 6.74, the internal resistance of the cell is negligible. For the value of R = 40//x Omega , no current flows through the galvanometer. What is x ?

In the figure shown wire AB has a length of 100 cm and resistance 8Omega . Find the balance point length l .

3V poteniometer used for the determination of internal resistance of a 2.4V cell. The balanced point of the cell in open circuit is 75.8cm. When a resistor of 10.2Omega is used in the external circuit of the cell the balance point shifts to 68.3cm length of the potentiometer wire. The internal resistance of the cell is

The length of a potentiometer wire is l . A cell of emf E is balanced at a length l/3 from the positive end of the wire. If the length of the wire is increased by l/2. At what distance will the same cell give a balance point.

A mete bridge is used to determine the resistance of an unknown wire by measuring the balance point length l. If the wire is replaced by another wire of same material but with double the length and half the thickness the balancing point is expected to be

In the circuit shows in Fig. the initail current through the inductor at t = 0 is I_(0) . After a time t = L//R , the switch is quickly shifted to position 2. a. Plot a graph showing the variation of current with time. b. Calculate the value of current in the inductor at t = (3)/(2) (L)/(R ) .

An accumulator of emf 2 V and negligible internal resistance is connected across a uniform wire of length 10 m and resistance 30 Omega The appropriate terminals of a cell of emf 1.5 V and internal resistance 1 Omega is connected to one end of the wire and the other terminal of the cell is connected through a sensitive galvanometer to a slider on the wire. What is the length of the wire that will be required to produce zero deflection of the galvanometer? How will the balancing length change? (a) When a coil of resistance 5Omega is placed in series with the accumulator. (b) The cell of 1.5 V is shunted with 5 Omega resistor?