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When a galvanometer is shunted with a 4O...

When a galvanometer is shunted with a `4Omega` resistance, the deflection is reduced to `1//5`. If the galvanometer is further shounted with a `2Omega` wire, the new deflection will be (assuming the main current remains the same)

A

`5/9` of the deflection when shunted with `4Omega` only

B

`5/13` of the deflection when shunted with `4Omega` only

C

`1/13` of the original deflection

D

`1/9` of the original deflection

Text Solution

Verified by Experts

Case -I
`I//5=(I(4))/(G+4)`
`G+4=20`
`G=16 Omega`

`I=(I(4//3))/16+4/3=I/13`
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