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The length of a wire of a potentiometer ...

The length of a wire of a potentiometer is 100 cm, and the emf of its cell is E volt. It is employed to measure the emf of a battery whose internal resistance is `0.5Omega`. If the balance point is obtained at l = 30 cm from the positive end, the emf of the battery is

A

`(30E)/100.5`

B

`(30E)/(100-0.5)`

C

`(30(E-0.5I))/100` where I is the current in the potentiometer wire

D

`(30E)/100`

Text Solution

Verified by Experts

`V prop 1 therefore V/E=l/L`
where,=I balance point distance
L= length of potentiometer wire or `V=i/L E or V=(30 times E)/100=30/100E`
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