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Shown in the figure below is a meter-bri...

Shown in the figure below is a meter-bridge set up with null deflection in the galvanometer

The value of the unknown resistor R is

A

`13.75Omega`

B

`220 Omega`

C

`110 Omega`

D

`55 Omega`

Text Solution

Verified by Experts

When bridge is balanced, ratio of resistance in opposite arms is equal
`P/Q=R/S`
Given `P=55 Omega,Q=R`
As `R prop i_1` where `l_1=20cm`
`s prop l_2` where `l_2=100-20=80 cm`
`R/S=J_1/J_2=20/80 therefore 55/R=20/80 or R=220 Omega`
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