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The resistivity of a potentiometer wire ...

The resistivity of a potentiometer wire is `40xx10^(-8)Omega-m` and its area of cross-section is `8xx16^(-6)m^(2)`. If `0.2` A current is flowing through the wire, the potential gradient will be

A

0.2Vlm

B

1Vlm

C

0.3Vlm

D

0.1Vlm

Text Solution

Verified by Experts

Potential gradient of a potentiometer,
`K=V/I=(IR)/l=(Ipl)/(la)`
`implies K=(JD)/A=(0.2 times 4 times 10^-7)/(8 times 10^-7)=0.1V//m`
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