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In a large building, there are 15 bulbs ...

In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of electric mains is 220 V. The minimum capacity of the main fuse of the building will be :

A

8A

B

10A

C

12A

D

14A

Text Solution

Verified by Experts

Total power (P) consumed=`(15 times 40)+(5 times 100)+(5 times 80)+(1 times 1000)=2500W`
As we know that P=Vl `implies I=2500/220=125/11=11.36A`
Hence minimum capacity should be 12A
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