Three moles of `CO_(2)` gas expands isothermally (in thermal contact with the surroundings, temperature `= 15.0^(@)C`) against a fixed external pressure of `1.00` bar. The initial and final volumes of the gas are `10.0 L` and `30.0L`, respectively. ltbr. Change in entropy of the universe is

Options

A. 11.6 V and 11.7 V
B. 11.5 V and 11.6 V
C. 11.4 V and 11.5 V
D. 11.7 V and 11.8 V

Explanation

For parallel combination of cells,
`E_(eq)=(E_1/r_1+E_2/r_2)/(1/r_1+1/r_2) therefore E_(eq)=(12/1+13/2)/(1/2+1/2)=37/3 V`
Potential drop across `10Omega` resistance
`V=(E/(R_(eq))) times 10=(37//3)/((10+2/3)) times 10=11.56V`
Alternative method
Applying KVL in loop ABCFA,`-12+10(I_1+I_2) +1 times I_1=0`
`implies 12=11I_1+10I_2` .......(i)
Similarly in loop ABDEA, `-13+10(I_1+I_2)+2 times I_2=0`
`implies 12=10I_1+12I_2`..........(ii)
SOlving Eqs (i) and (ii) we get `I_1=7/16A,I_2=23/32A`
`therefore` VOltage drop across `10Omega` resistance is `V=10(7/16+23/32)=11.56V`