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In a Wheatstone bridge (see fige ) Res...

In a Wheatstone bridge (see fige ) Resitances P and Q are approximately equal .When `R= 400 Omega` the bridge is blanced .on is inerchanging P and Q ,the value of R, for balance is 405 `Omega ` .The value of X is close to :

A

401.5 ohm

B

402.5 ohm

C

403.5 ohm

D

404.5 ohm

Text Solution

Verified by Experts

Let the ratio `P/Q be `1+delta ` <
where `Delta gt gt 1` , So, `400/x=1+ delta and 405/x=1/(1+delta) 1- delta`
Adding `400/x+405/x 2`, Solving `x 402.5 Omega`
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