In the given circuit diagram, the currents, `I_1=-0.3A,I_4=0.8A` and `I_5=0.4A`, are flowing as shown. The currents `I_2,I_3` and `I_6` respectively, are :

Options

A. 0.4A,0.4A,1.1A
B. 0.4A,1.1A,0AA
C. 1.1A,-0.4A,0.4A
D. 1.1A,0.4A,0.4A

Explanation

`I_1=-0.3A, I_4=0.8A, I_3=0.4A`
`I_6+I_3=I_2+I_1`
`I_6+I_3=I_2-0.3A`………(i)
`I_5+I_3=I_4`……….(ii)
`0A+I_3=0B, I_3=0.4A`
`I_2=I_1=I_4`
`I_2-0.3=0.8`
`I_2=1.1A, I_5=I_6=0.4A`