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For the circuit shown, with R(1)=1.0Omeg...

For the circuit shown, with `R_(1)=1.0Omega,R_(2)=2.0Omega,E_(1)=2V` and `E_(2)=E_(3)=4V`, the potential difference between the points `'a'` and `'b'` is approximately (in `V`):

A

3.7

B

2.7

C

3.3

D

2.3

Text Solution

Verified by Experts

`R_1=V^2/P=(220)^2/25=1936 Omega`
`R_2=(220)^2/100=484 Omega`
`i=220/(1936+484)=220/2420=1/11 Amp`
`P_1=i^2 R_1=1/121 times 1936=16w`
`P_2=i^2 times P_2=1/121 times 484=4W`
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