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In an experiment, the resistance of a ma...

In an experiment, the resistance of a material is plotted as a function of temperature (in some range).As shown in the figure, it is a straight line.

One may conclude that :

A

`R(T)=R_0e^(-T^2//T_0^2)`

B

`R(T)=R_0/T^2`

C

`R(T)=R_0e^((-T_0^2)/T^2)`

D

`R(T)=R_0e^(T^2//T_0^2)`

Text Solution

Verified by Experts

In R varies linearly with `1/T^2`
So, IN `R=-M(1/T^2)+C[m gt 0, c gt 0]` Using `Y=-mx+c, R=e^(0-m/T^2)=e^c.e ^(-m/T^2)`
Or `R=R_0 e^(-m//T^2)` type of form will do good
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