A moving coil galvanometer allows a full scale current of `10^(-4)` A. A series resistance of `2 Momega` is required to convert the above galvonometer into a voltmeter of range 0-5 V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0-10 mA is: a) 500Ω b) 100Ω c) 200Ω d) 10Ω

Options

A. `10Omega`
B. `100Omega`
C. `500Omega`
D. `200Omega`

Explanation

For voltmeter `j_g//max(R_g+R)=V_(max). Or R_g(V_(max))/(i_(g,max))-R-(5/10^-4-2 times 10^6)`=negative
As an ammeter
`i_G times R_G=(i-i_a) times S, S=(i_G times R_G)/(i-i_G)=(10^-4 times R_G)/((10^-2 -10^-4))=10^-2 R_G`=negative
`therefore` No any possible Some data is question error