To verify Ohm's law, a student connects the voltmeter across the battery as shown in the figure. The measure voltage is plotted as a function of the current, and the following graph is obtained


if `V_(O)` is almost zero. identify the correct statement

Options

A. The value of the resistance R is `1.5Omega`
B. The emf of the battery is 1.5 V and the value of R is `1.5Omega`
C. The potential difference across the battery is 1.5V when it sends a current of 1000 mA
D. The emf of the battery is 1.5V and its internal resistance is `1.5Omega`

Explanation

`I=0,V=1.5V=e therefore e=1.5V, I=1000mA=1A`
`V=0 implies e-Ir=0 implies 1.5-1 times r=0 ,r=1.5 Omega`