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A resistance of 2Omega is connected acro...

A resistance of `2Omega` is connected across one gap of a meter bridge (the length of the wire is `100 cm`) and an unknown resistance, greater than `2Omega`is conneted across the other gap. When these resistances are interchanged, the balance point shifts by `20 cm`. Neglecting any corrections,the unknown resistance is

A

`3Omega`

B

`4Omega`

C

`5Omega`

D

`6Omega`

Text Solution

Verified by Experts

`R gt 2 Omega therefore 100-x gt x`

Applying `P/Q=R/S`
We have, `2/R=x/(100-x)`………(i)
`R/2=(x+20)/(80-x)`…..(ii)
On solving equation (i) and (ii) we get `R=3 Omega`
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