A meter bridge is set- up as shown in figure, to determine an unknown resistance `X` using a standard ` 10 Omega` resistor. The galvanometer shows null point when tapping - key is at `52 cm` mark. The end -corrections are `1 cm` and `2 cm` respectively for the ends `A` and `B`. The determined values of `X` is .

(a) `10.2 Omega`
(b) `10.6 Omega`
(c) `10.8 Omega`
(d) `11.1 Omega`.

Options

A. `10.2Omega`
B. `10.6Omega`
C. `10.8Omega`
D. `11.1 Omega`

Explanation

Using the concept of balanced Wheat stone bridge ,we have
`P/Q=R/S implies X/((52+1))=10/((48+2)) therefore X=(10 times 53)/50=10.6 Omega`