Two identical moving coil galvanometers have `10Omega` resistance and full scale deflection at `2muA` current. One of them is converted into a voltmeter of 100mA full scale reading and the other into an Ammeter of 1mA full scale current using appropriate resisters. These are then used to measure the voltage and current in the Ohm’s law experiment with `R=1000 Omega` resistor by using an ideal cell. Which of the following statement(s) is(are) correct?

Options

A. If the ideal cell is replaced by a cell having internal resistance of`5Omega` then the measured value of R will be more than `1000Omega`
B. The resistance of the Ammeter will be`0.02Omega` (round off to 2nd decimal place)
C. The resistance of the voltmeter will be `100kOmega`
D. The measured value of will be `978Omega lt R lt 980 Omega`

Explanation

To solve the problem, we need to analyze the conversion of the galvanometers into a voltmeter and an ammeter, and then use them in an Ohm's law experiment with a resistor of \( R = 1000 \, \Omega \).

### Step-by-Step Solution:

1. **Convert the Galvanometer to a Voltmeter:**
- The galvanometer has a resistance \( R_g = 10 \, \Omega \) and full-scale deflection at \( I_g = 2 \, \mu A = 2 \times 10^{-6} \, A \).
- We want to convert it into a voltmeter with a full-scale reading of \( 100 \, mA = 0.1 \, A \).
- The voltage across the galvanometer at full-scale deflection is:
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