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The angular momentum of a particle about...

The angular momentum of a particle about origin is varying as L =4t+8(SI units) whern its moves along a straight line y=x-4(x,y in metres). The magnitude of force acting on the particle will be

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The correct Answer is:
1.41
L=4t + 8
Torque about the origin, `tau =(dL)/(dt) = 4N-m`,
`tau = r_(1)F , 4= r_(1)F`, where, `r_(1)` is the perpendicular distance of origin from a line:
`r_(1) =|(0-0-4)/(sqrt(1^(2) + 1^(2)))|=2sqrt(2)`
Force is acting along the straight line
`x-y-4=0`, `F=sqrt(2N) = 1.41 N`.
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