Home
Class 12
PHYSICS
A disc of mass M and radius R moves in t...

A disc of mass M and radius R moves in the x-y plane as shown in the figure. The angular momentum of the disc at tihe instant shows is

Text Solution

Verified by Experts

The correct Answer is:
5
Conserving angular momentum about point A on the ground,
`mV_(0)-I_(m)omega_(0)=0+0`
`mV_(0) -2/5 mr^(2)omega_(0)=0`
`omega_(0) =(5v_(0))/(2r)=5 md//s`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise LEVEL - 2 (Rotatinal Kinematics, Moment of Inertia)|10 Videos

  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise LEVEL - 2 (Torque, Fixed and Rotation)|10 Videos

  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise LEVEL - 1 (Mixed topics)|15 Videos

  • REVISION TEST-2 JEE

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos

  • SIMPLE HARMONIC MOTION

    VMC MODULES ENGLISH|Exercise 7-previous year question|46 Videos

Similar Questions

Explore conceptually related problems

A disc of mass m and radius R moves in the x-y plane as shown in Fig. The angular momentum of the disc about the origin O at the instant shown is

A disc of mass m and radius R is rolling without slipping as shown in the figure. The magnitude of net velocity of the point P is (OP = R/2)

A uniform disc of mass M and radius R is liffted using a string as shown in the figure. Then choose incorrect option(s),

Two identical uniform discs of mass m and radius r are arranged as shown in the figure. If alpha is the angular acceleration of the lower disc and a_(cm) is acceleration of centre of mass of the lower disc, then relation among a_(cm), alpha and r is

A disc of mass m and radius R is rolling on horizontal ground with linear velocity v. What is the angular momentum of the disc about an axis passing through bottommost point and perpendicular to the plane of motion ?

A system of uniform rod of mass m and length 2R and a uniform disc of m and radius R are as shown in the figure. The moment of inertia of the system about the axis OO^' (perpendicular to plane of disc) will be

A uniform disc of mass m and radius r and a point mass m are arranged as shown in the figure. The acceleration of point mass is : ( Assume there is no slipping between pulley and thread and the disc can rotate smoothly about a fixed horizontal axis passing through its centre and perpendicular to its plane )

A disc of mass M and Radius R is rolling with an angular speed omega on the horizontal plane. The magnitude of angular momentum of the disc about origin is:

A disc has mass 9 m. A hole of radius R/3 is cut from it as shown in the figure. The moment of inertia of remaining part about an axis passing through the centre 'O' of the disc and perpendicular to the plane of the disc is :

A uniform semicircular disc of mass 'm' and radius 'R' is shown in the figure. Find out its moment of inertia about. (a) axis 'AB' ( shown in the figure 0 which passes through geometrical centre and lies in the plane of the disc (b) axis 'CD' which passes through its centre of mass and it is perpendicular to the plane of the disc.